Answer:
Step-by-step explanation:
from
3(7x +7) + 5x = 5(5x + 10)
21x+21+5x = 25x + 50
26x + 21 = 25x + 50
26x-25x +21 = 50
1x+21 = 50
1x =50-21
x = 29
equal when x= 29
try to x> 29 such as 30
3(7(30) +7) + 5(30) ? 5(5(30) + 10)
1470 ? 800
so greater than when x >29
finally
less than when x<29
Answer:
When x = 29: the expressions are equal
When x < 29: 3(7x + 7) + 5x is less than 5(5x + 10)
When x > 29: 3(7x + 7) + 5x is greater than 5(5x + 10)
Step-by-step explanation:
Given expressions:
Expand both expressions:
3(7x + 7) + 5x
⇒ 21x + 21 + 5x
⇒ 26x + 21
5(5x + 10)
⇒ 25x + 50
Equate the expanded expressions and solve for x
26x + 21 = 25x + 50
⇒ 26x - 25x = 50 - 21
⇒ x = 29
Therefore, the expressions are equal when x = 29
When x < 29: 3(7x + 7) + 5x < 5(5x + 10)
When x > 29: 3(7x + 7) + 5x > 5(5x + 10)
