Respuesta :

Answer:

[tex]\cos\theta = \pm\frac{2\sqrt{2}}{3}\\\tan\theta=\pm\frac{\sqrt{2}}{4}[/tex]

Step-by-step explanation:

sinθ = 1/3

[tex]\cos\theta=\pm\sqrt{1-\cos^2\theta} = \pm\sqrt{1-\frac{1}{9}}=\pm\sqrt\frac{8}{9}=\pm\frac{2\sqrt{2}}{3}[/tex]

[tex]\tan\theta=\frac{\sin\theta}{\cos\theta}=\pm\frac{1}{2 \sqrt{2}}=\pm\frac{\sqrt{2}}{4}[/tex]