The work done by friction on the car as it makes the turn is [tex]2.514 \times 10^6 \ J[/tex].
The kinetic friction of the car produces the centripetal force needed to keep the car in the circular path.
[tex]Ff = F_c = \frac{mv^2}{r}\\\\ F_c = \frac{1000 \times 20^2}{125} \\\\F_c = 3200 \ N[/tex]
[tex]d = 2\pi r\\\\d = 2\times 3.142 \times 125\\\\d = 785.5 \ m[/tex]
The work done by friction on the car as it makes the turn is calculated as follows;
[tex]W = F_c d\\\\W = 3200 \times 785.5\\\\W = 2.514 \times 10^6 \ J[/tex]
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