Respuesta :
The molar mass of the acid is 83 g/mol
Stoichiometry
From the question, we are to determine the Molar mass of the acid.
From the given information,
The acid reacts with sodium hydroxide in a 1:2 ratio
This means 1 mole of the acid reacts with 2 moles of sodium hydroxide
First, we will calculate the number of moles of NaOH present.
Volume of NaOH = 10.0 mL = 0.01 L
Concentration of NaOH = 0.800 M
Using the formula,
Number of moles = Concentration × Volume
Number of moles of NaOH present = 0.800 × 0.01
Number of moles of NaOH present = 0.008 moles
If, 1 mole of the acid reacts with 2 moles of sodium hydroxide
Then,
0.004 moles of the acid will react with the 0.008 moles of sodium hydroxide
Thus, number of moles of the acid that reacted is 0.004 moles
Now for the Molar mass of the acid
From the formula,
[tex]Molar\ mass = \frac{Mass}{Numbber\ of\ moles}[/tex]
From the given information,
Mass of the acid = 0.664 g
Therefore,
[tex]Molar \ mass \ of \ the \ acid \ = \frac{0.664}{0.004}[/tex]
Molar mass of the acid = 166 g/mol
Hence, the molar mass of the acid is 166 g/mol
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