Respuesta :
Answer:
Alvin's Age is 81 and Elga's age is 27
Step-by-step explanation:
let A be Alvin's age and E be Elga's age
A = 3 E (alvin's age is three times elga's age)
A + E = 108 ( the sum of their ages is 108)
3E + E = 108
4 E = 108
E= 108/4 = 27
A = 3E = 27*3 = 81
⭐ Let the Alvin's age be "a" and the Elga's age be "e".
⭐ If we carefully identify the question, we can get two hints provided in the question which can be framed into equations. They are,
- A = 3E ... (1)
(Alvin's age is 3 times the age of Elga's age)
- A + E = 108 ... (2)
(The sum of Alvin's and Elga's age is 108)
Substituting value of A i.e (A = 3E) in eqn (2) so as to get same variable and solve the eqn.
[tex]\Rrightarrow\bf{a + e = 108}[/tex]
[tex]\Rrightarrow\bf{3e + e = 108}[/tex]
[tex]\Rrightarrow\bf{4e = 108}[/tex]
[tex]\Rrightarrow\bf{e = \frac{108}{4} }[/tex]
[tex]\Rrightarrow\bf{e = 27}[/tex]
Substituting value of (e = 27) in eqn (1),
[tex]\Rrightarrow\bf{a = 3e}[/tex]
[tex]\Rrightarrow\bf{a = 3 \times 27}[/tex]
[tex]\Rrightarrow\bf{a = 81}[/tex]
- Thus, the age of Alvin is 81 years and that if Elga is 27 years
