A running back with a mass of 74 kg and a speed of 9 m/s collides with, and is held by, a 111-kg defensive tackle going in the opposite direction. How fast must the tackle be going before the collision for their speed afterward to be zero? in m/s

This question involves the concepts of the law of conservation of momentum.
The tackle must be moving with a velocity of "6 m/s".
According to the Law of Conservation of Momentum, the total momentum of an isolated system always remains constant. Therefore,
[tex]Total\ Momentum\ Before\ Collision =Total\ Momentum\ After\ Collision \\\\m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
Therefore,
[tex](74\ kg)(9\ m/s)+(111\ kg)(u_2)=(74\ kg)(0\ m/s)+(111\ kg)(0\ m/s)\\\\u_2=\frac{-(74\ kg)(9\ m/s)}{111\ kg}[/tex]
u₂ = - 6 m/s
negative sign shows opposite direction.
Learn more about the Law of Conservation of Momentum here:
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