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The function f(t)=9900(1.0015)^{10t}f(t)=9900(1.0015)
10t
represents the change in a quantity over t decades. What does the constant 1.0015 reveal about the rate of change of the quantity?

Respuesta :

Using exponential function concepts, it is found that the constant 1.0015 reveals that the quantity increases by 0.15% each decade.

What is an exponential function?

An increasing exponential function is modeled by:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

  • A(0) is the initial value.
  • r is the growth rate, as a decimal.

In this problem, the function is:

[tex]f(t) = 9900(1.0015)^{10t}[/tex]

In which t is the time in decades.

The growth rate is r = 0.0015, as [tex]1 + r = 1.0015 \rightarrow r = 0.0015[/tex], hence the constant 1.0015 reveals that the quantity increases by 0.15% each decade.

You can learn more about exponential function concepts at https://brainly.com/question/25537936

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