the position of a simple harmonic oscillator is given by x(t) = (0.50 m) cos(πt/3) where t is in seconds. (i) what is the maximum velocity of this oscillator?

Respuesta :

leena

Hi there!

The maximum velocity is given by:

[tex]\large\boxed{v_{max} = Aw}}[/tex]

A = amplitude (m)

ω = angular frequency (rad/sec)

From the parent equation of an SHM oscillator:

[tex]\large\boxed{x(t) = Acos(\omega t + \phi)}}[/tex]

The given equation provides us with the amplitude and angular frequency, so we can take these values from the equation to solve for the max velocity:

[tex]v_{max} = \pm(0.5)(\frac{\pi}{3}}) = \boxed{\pm \frac{\pi}{6} = \pm0.524 m/s}}[/tex]