Answer:
A
Step-by-step explanation:
Using the rules of logarithms
log[tex]x^{n}[/tex] = n logx
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
Given
[tex]\frac{1}{2}[/tex][tex]log_{x}[/tex] 64 = 3
[tex]log_{x}[/tex][tex]64^{\frac{1}{2} }[/tex] = 3
[tex]log_{x}[/tex] 8 = 3
8 = x³
2³ = x³ , then
x = 2
