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Six apples and three oranges cost $3.36. Two apples and five oranges cost $3.04. Find the cost of one apple and the cost of an orange.

Answer and step-by-step explanation pls!!

Respuesta :

Answer:

$0.8

Step-by-step explanation:

let x represent the price of apples

let y represent the price of oranges

6x+3y=3.36—eqn 1

2x+5y=3.04—eqn 2

Multiply eqn 2 by 3

3(2x+5y=3.04)=6x+15y=9.12

Subtract eqn 2 from 1

6x+3y=3.36

-{6x+15y=9.12}

-12y=-5.76

y=0.48

plug y=0.48 into eqn 1

6x+3(0.48)=3.36

6x=3.36-1.44

x=1.92/6=0.32

That is, an apple costs $0.32 and an orange costs $0.48

Therefore the cost of an orange and an apple=$0.48+$0.32=$0.8

Answer:

  • apple: $0.32
  • orange: $0.48

Step-by-step explanation:

Let x and y represent the costs of 1 apple and 1 orange, respectively. The two cost figures tell us ...

  6x +3y = 3.36

  2x +5y = 3.04

We note that all of the numbers in the first equation are divisible by 3, so we can divide by 3 to reduce it to ...

  2x +y = 1.12

Subtracting this from the second equation gives ...

  (2x +5y) -(2x +y) = (3.04) -(1.12)

  4y = 1.92 . . . . . . . simplify

  y = 0.48 . . . . . . . divide by 4

Then the cost of an apple can be found from our reduced equation:

  2x +0.48 = 1.12 . . . substitute for y

  2x = 0.64 . . . . . . . . subtract 0.48

  x = 0.32 . . . . . . . . . divide by 2

The cost of one apple is $0.32; the cost of one orange is $0.48.

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Additional comment

The method of solution we used here is called "elimination," because the x-variable was eliminated from the combined equations. There are numerous other methods available for solving a system of linear equations. Most graphing calculators have features for graphing and for reducing matrices that will solve these for you. All you need to do is enter the equations.

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