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A man moves a box horizontally by exerting on it a force of 90 N directed at 60 above the horizontal. If the work done on the box is 450 J, the displacement of the box is

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leena

Hi there!

We know that:

W = F · dcosФ

The cosine indicates that work only takes into account the component of the force that is parallel to the displacement.

Thus, we must find the horizontal component of the force:

FcosФ = horizontal component

90cos(60) = 45 N

Now, we can solve for displacement:

W = Fd

W/F = d

450/45 = d = 10 m

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