A volume of 10.0 mL of 25 mg/L Mn2+ solution was diluted to make a solution with the final volume of 50.0 mL. Calculate the concentration (in mg/L) of the final solution

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31-10-2021
Chemistry

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A volume of 10.0 mL of 25 mg/L Mn2+ solution was diluted to make a solution with the final volume of 50.0 mL. Calculate the concentration (in mg/L) of the final solution

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CintiaSalazar CintiaSalazar · Answer 1 · 2021-11-12T16:19:51+01:00

Taking into account the definition of dilution, the concentration of the final solution is 5 mg/L.

First of all, you have to know that dilution is the reduction in concentration of a chemical in a solution. The process consists of adding more solvent to the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

In this case, you know:

Ci= 25 mg/L
Vi= 10 mL
Cf= ?
Vf= 50 mL

Replacing in the definition of dilution:

25 mg/L × 10 mL= Cf × 50 mL

Solving:

Cf= (25 mg/L × 10 mL)÷ 50 mL

Cf= 5 mg/L

In summary, the concentration of the final solution is 5 mg/L.

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