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Consider the equation c= ax-bx, where a,b, and c are whole numbers. Which of the following result in values of a, b, and c so that the original equation has exactly one solution? Justify your answers.

1.) a-b=1, c=0
2.) a=b, c≠0
3.) a=b, c=0
4.) a≠b, c=0

Respuesta :

[tex]\\ \sf\longmapsto c=ax-bx[/tex]

  • Take x common

[tex]\\ \sf\longmapsto c=x(a-b)[/tex]

  • If a-b=1 then c=-x(infinite solutions)

If a=b

[tex]\\ \sf\longmapsto c=0[/tex]

Option C is the correct ans

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