contestada

Suzie Lavtaski has reached the end of the ski slope and abruptly decelerates from 29.0 m/s to 1.8 m/s in 1.45 seconds. determine the acceleration rate and the distance she moved during the breaking period.

Respuesta :

arthurpdc
Using [tex]v=v_0+at[/tex]:

[tex]1.8=29+a\cdot1.45\iff 1.45a=-27.2\iff \boxed{a\approx-18.76~m/s^2}[/tex]

Using [tex]v^2=v_0^2+2a\Delta S[/tex]:

[tex]1.8^2=29^2+2(-18.76)\Delta S\\\\ 3.24=841-37.52\Delta S\\\\ \Delta S=\dfrac{841-3.24}{37.52}\iff\boxed{\Delta S\approx22.33~m}[/tex]

Otras preguntas