Answer:
II and III
Step-by-step explanation:
Parallel lines have the same gradient, they will have the same coefficient in front of x
II: 2x + 3y = 6 needs to be rearranged to 3y = -2x + 6 and then y = -2/3x + 2: the gradient is -2/3
III: y - 8 = -2/3(x - 3) needs to expanded so y - 8 = -2/3x + 2 and then y = -2/3x + 10: again, the gradient is -2/3
The two lines are parallel because both gradients are -2/3
Hope this helps!
