rihannaclarke1211
contestada

use elimination method

show step by step please

3x-2y=10

2x+5y=13

here an example

3x+y=13 equ.1

5x-2y=7 equ.2

Multiply equ 1 by equ 2

6x+2y=26 equ.3

5x-2y=7 equ.2

Add equ.2 and equ.3

11x+0=33

11x=33

x=33\11

x=3

when x=3 in equ.1

3(3)+y=13

9+y=13

y=13-9

y=4

x=3 y=4

That how you must work it

Respuesta :

rspill6

Answer:

Step-by-step explanation:

3x-2y=10     [E1]

2x+5y=13    [E2]

5*(3x-2y=10)     [mutiply E1 by 5 to bring -2x to -10x]

15x-10y=50      

2*(2x+5y=13)  [mutiply E2 by 2 to bring 5x to 10x]

4x+10y=26

15x-10y=50    [Now add E1 and E2 - the x cancels out]

4x+10y=26

19x = 76  

x = 4              

Solve for y:  

3x-2y=10

3*4 - 2y = 10

-2y = -2

y = 1

x = 4 and y = 1

Use these results in the two equations and see if they work.  [They do]

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