Answer:
[tex]5 cups[/tex]
Step-by-step explanation:
TO know the answer to this problem you just have to add up the number of cups that each one carried:
[tex]2(\frac{1}{4} )+2(\frac{1}{2} )+2(\frac{3}{8} )+3(\frac{5}{8} )+\frac{7}{8}=\\(\frac{2}{4} )+(\frac{6}{8} )+(\frac{2}{2} )+(\frac{15}{8} )+\frac{7}{8}=\frac{40}{8} \\\frac{40}{8} =5[/tex]
By adding them up we know that all together carried 40/8 cups, so between all of them they carried 5 cups.
