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28-12-2016
Mathematics

contestada

GEOMETRY
Three of the labeled points are chosen at random. What is the probability that they are collinear?

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Аноним Аноним

31-12-2016

The solution to the problem is as follows:

There are (5/3) = 10 sets of three points.

There are 2 sets which are collinear: EDC, and EAB

Therefore: P ( 3 points collinear ) = 2/10 = 1/5

I hope my answer has come to your help. God bless and have a nice day ahead!

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