Respuesta :
The kinematics for the uniform motion can be found to be correct is:
D. (a) 34 s (b) 119 m (c) 44 m
Parameters given
- The distance x = 75 m
- Average velocity of father and daughter v₁ = 2.2 m/s and v₂ = 3.5 m/s
To find
a) The travel time
b) The distance traveled by the daughter
c) How much does the daughter exceed the stop if she is going in a straight line
Kinematics studies the movement of bodies, finding relationships between position, velocity and acceleration.
In the special case that the acceleration is zero, the motion is called uniform motion and is described by the relation
[tex]v_{avg}[/tex] = [tex]\frac{\Delta x}{\Delta t}[/tex]
Where v_avg is the mean speed, Δx and Δt are the variation of distance and time in the interval
a) Since the father travels in a straight line to the bus, his distance is
x=75m
Δt = [tex]\frac{\Delta x}{v_1}[/tex]
Δt = [tex]\frac{75}{2.2}[/tex]
Δt = 34.09 s
This time is the same for both since they indicate that they arrive together
b) The distance traveled by the daughter
Δx₂ = v₂ Δt
Δx₂ = 3.5 34.09
Δx₂ = 119.32 m
c) If the daughter's trip had been in a free straight, she would open after the stop
Δx = Δx₂ - 75
Δx = 119.32 -75
Δx = 44.2 m
In conclusion using the kinematic relations for the uniform motion we can find that the answers are:
a) The travel time is 34.09 s
b) The distance traveled by the daughter is 119.32 m
c) The daughter passed the stop by a distance of 44.2 m
Reviewing the answers we find that the correct one is:
d) (a) 34 s (b) 119 m (c) 44 m
learn more about uniform motion here:
brainly.com/question/12920060
