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PLZZZ HELP ME
What are two different ways 2/3x = 10 could be solved for x? MORE THAN ONE ANSWER

Subtract 3/2 from both sides of the equation

Divide both sides of the equation by 3/2

Divide both sides of the equation by 2/3

Multiply both sides of the equation by 3/2

Multiply both sides of the equation by 2/3

Subtract 2/3 from both sides of the equation​

Respuesta :

adioabiola

Here, we are required to determine what two different ways (2/3)x = 10 could be solved for x.

The correct answers are;

  • Divide both sides of the equation by 2/3
  • Multiply both sides of the equation by 3/2

While solving linear equations of a single variable such as this, to evaluate the value of the variable, (x in this case scenario), there's a need to get rid of the coefficient of the variable (which is (2/3) in this case).

As such, there are two different ways to get rid of the coefficient of the variable in cases like this;

  • First is to divide both sides of the equation by the coefficient of the variable. Thus;
  • First is to divide both sides of the equation by the coefficient of the variable. Thus;By dividing both sides of the equation by (2/3); we can obtain;
  • First is to divide both sides of the equation by the coefficient of the variable. Thus;By dividing both sides of the equation by (2/3); we can obtain; {(2/3)x/(2/3)} = 10/(2/3)

Therefore, x = 30/2 = 15

  • The second approach is to multiply both sides of the equation by the reciprocal (inverse) of the coefficient. Thus;
  • The second approach is to multiply both sides of the equation by the reciprocal (inverse) of the coefficient. Thus;By multiplying both sides by 3/2, we have;

x = 10 × (3/2). = 15.

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