Respuesta :
Using the normal distribution, it is found that 0.3253 of observations lie between z = 0.15 and z = 1.20.
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Normal Probability Distribution
In a normally distributed data-set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- Each z-score has an associated p-value, which is the percentile of X.
- The proportion of observations lie between z = 0.15 and z = 1.20 is the p-value of Z = 1.20 subtracted by the p-value of p-value of Z = 0.15.
- These p-values are found looking at the z-table.
- z = 1.2 has a p-value of 0.8849.
- z = 0.15 has a p-value of 0.5596.
Thus:
0.8849 - 0.5596 = 0.3253
0.3253 of observations lie between z = 0.15 and z = 1.20.
A similar problem is given at https://brainly.com/question/16347292
