Answer:
• from the quadratic formula:
[tex]{ \boxed{ \rm{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }}} \\ [/tex]
• a → 1, b → 1, c → -2:
• substitute:
[tex]{ \tt{x = \frac{ - 1± \sqrt{ {1}^{2} - (4 \times 1 \times - 2) } }{(2 \times 1)} }} \\ \\ { \tt{x = \frac{ - 1± \sqrt{9} }{2} }} \\ \\ { \tt{x = \frac{ - 1±3}{2} }} [/tex]
• Find values of x:
[tex]{ \boxed{ \tt{x = \frac{ - 1 + 3}{2} }}} \: \: { \tt{and}} \: \: { \boxed{ \tt{x = \frac{ - 1 - 3}{2} }}} \\ \\ { \boxed{ \tt{x = 1}}} \: \: { \tt{and}} \: \: { \boxed{ \tt{x = - 2}}}[/tex]
