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27-09-2021
Chemistry

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What is the temperature of 0.620 mol of gas at a pressure of 1.5 atm and a volume of 10.9 L ? Express your answer using two significant figures.

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27-09-2021

Answer:

320K

Explanation:

PV=nRT

1.5atm(10.9L)=(0.620mol)(0.08206 L atm/ mol K)T

T=320K

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