Hii :))
[tex] \tt(2x - 3) ^{2} \\ = \tt( 2 {x})^{2} - 2 \times 2x \times 3 + 3 ^{2} \\ = \boxed{ \tt 4 {x}^{2} - 12x + 9}[/tex]
Just use the (a - b)² algebraic identity which is equal to a² - 2ab + b².
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