Respuesta :

mhanifa

Answer:

Use the following identity:

  • a³ + b³ + c³ = 3abc if a + b + c = 0

Substitute:

  • a = 3x, b = 5y, c = 4z

and get:

  • (3x)³ + (5y)³ + (4z)³ = 3(3x)(5y)(4z)
  • 27x³ + 125y³ + 64z³ = 180xyz

We know

If a+b+c=0

[tex]\boxed{\sf a^3+b^3+c^3=3abc}[/tex]

[tex]\\ \sf\longmapsto 3x^3+5y^3+4z^3=3(3x)(5y)(4z)[/tex]

  • Simplify

[tex]\\ \sf\longmapsto 27x^3+125y^3+64z^3=180xyz[/tex]

Hence proved

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