Answer:
The least of the three integers is 1.
Step-by-step explanation:
Hi there!
Let x be equal to the least of these integers.
Let x+1 and x+2 be the next consecutive integers.
We're given that these integers have a sum os 6.
We can use these to construct an equation:
[tex](x)+(x+1)+(x+2)=6[/tex]
Combine like terms:
[tex]x+x+1+x+2=6\\x+x+x+1+2=6\\3x+3=6\\3x=3\\x=1[/tex]
Therefore, the least of these integers is 1.
The other two integers would be 2 and 3.
I hope this helps!
