Respuesta :

Step-by-step explanation:

By Completing the Square,

[tex]\begin{align}f(x)&=-2x^2+4x+6\\&=-2(x^2-2x)+6\\&=-2(x^2-2x+1)+8\\&=-2(x-1)^2+8 \end{align}[/tex]

Since the first tern is at most zero, the maximum value occurs when

[tex]x=1, f(x)=8[/tex]