Respuesta :

Answer:

[tex]{ \sf{2Cr _{(s)} + 3Cl _{2(g)} → 2CrCl _{3(g)} }}[/tex]

Answer:

to balance this equation it would be best to put a 2 infront of cr and crcl3.and a 3 in front of cl2 that way you will have 6 cl,and 2 cr on both sides

2Cr(s)+3Cl2(g)----->2CrCl3

I hope this helps