Respuesta :

caylus

Answer:

Hello,

Step-by-step explanation:

(x-3)*(x+4)=0 or x²+x-12=0

kamilmatematik100504

Answer:

Step-by-step explanation:

[tex]\displyastyle \Large \boldsymbol{} (x-x_1)(x-x_2) \ \ x_1 \ ; \ x_2 -roots \\\\(x-3)(x-(-4))=(x-3)(x+4)=\boxed{x^2+x-12}[/tex]