Answer:
[tex]\begin{array}{ccc}{Error} & {f} & {RF} & {Pilot} & {384} & {0.242} & {Human} & {69} & {0.043} & {Weather} & {362}& {0.228}& {Mechanical} & {435}& {0.274} & {Sabotage} & {338}& {0.213} \ \end{array}[/tex]
The most serious threat is mechanical problems.
Step-by-step explanation:
Given
[tex]Pilot \to 384[/tex]
[tex]Human \to 69[/tex]
[tex]Weather \to 362[/tex]
[tex]Mechanical \to 435[/tex]
[tex]Sabotage \to 338[/tex]
Solving (a): The relative frequency table
The relative frequency (RF) is calculated as:
[tex]RF = \frac{Frequency}{Total\ Frequency}[/tex]
Where
[tex]Total\ Frequency = 384 + 69 + 362+ 435 +338[/tex]
[tex]Total\ Frequency = 1588[/tex]
So, the relative frequencies is as follows:
[tex]Pilot = 384/1588 = 0.242[/tex]
[tex]Human = 69/1588 = 0.043[/tex]
[tex]Weather = 362/1588 =0.228[/tex]
[tex]Mechanical = 435/1588 = 0.274[/tex]
[tex]Sabotage = 338/1588 = 0.213[/tex]
So, the relative frequency table is:
[tex]\begin{array}{ccc}{Error} & {f} & {RF} & {Pilot} & {384} & {0.242} & {Human} & {69} & {0.043} & {Weather} & {362}& {0.228}& {Mechanical} & {435}& {0.274} & {Sabotage} & {338}& {0.213} \ \end{array}[/tex]
Solving (b): The most serious threat
The most serious threat is the one with the highest frequency, and that is the mechanical problems.
Carrying out maintenance schedule and removal of potential threat are some of the ways it can be minimized.
