5.A shipment of 200microwavescontains twentydefective units. In how many ways can a vending company buy fifteenof thesemicrovavesand receivea.No defective units(2pts)b.Exactly two defective units.(2pts)c.At least one defective unit.(2pts)

Respuesta :

Answer:

Step-by-step explanation:

Total no. of goods, n = 200

no. of defective units in the goods, d = 20

hence the no. of proper units,

g = n-d

g = = 200-20

g = 180

a)

ways in which a vending company buys fifteen of these microwaves and receive no defective units be:

[tex]^{180}C_{15}=\frac{180!}{15!\times (180-15)!}[/tex]

[tex]\approx 2.83\times 10^{21}[/tex]

b)

ways in which a vending company buys fifteen of these microwaves and receive exactly two defective units be:

[tex]^{20}C_2\times ^{180}C_{13}=\frac{20!}{2!\times (20-2)!} \times \frac{180!}{13!\times (180-13)!}[/tex]

[tex]\approx 190\times (2.146\times 10^{19})[/tex]

[tex]\approx 4.076\times 10^{21}[/tex]

c)

ways in which a vending company buys fifteen of these microwaves and receive at least one defective units be:

[tex]^{20}C_{1}\times ^{199}C_{14}=\frac{20!}{1!\times (20-1)!} \times \frac{199!}{13!\times (199-13)!}[/tex]

[tex]\approx 20\times (8.258\times 10^{19})[/tex]

[tex]\approx 1.652\times 10^{21}[/tex]