Respuesta :
(1,3) means x1 = 1 and y1 = 3
(4,-3) means x2 = 4 and y2 = -3
To find slope:
(y2-y1) / (x2-x1)
(-3-3) / (4-1)
-6 / 3
Slope is -2
To find intercept:
y-y1 = m(x - x1)
y - 3 = -2(x - 1)
y - 3 = -2x + 2
y = -2x + 5 :)
(4,-3) means x2 = 4 and y2 = -3
To find slope:
(y2-y1) / (x2-x1)
(-3-3) / (4-1)
-6 / 3
Slope is -2
To find intercept:
y-y1 = m(x - x1)
y - 3 = -2(x - 1)
y - 3 = -2x + 2
y = -2x + 5 :)
Answer:
2x + y = 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = C (1, 3) and (x₂, y₂ ) = D (4, - 3)
m = [tex]\frac{-3-3}{4-1}[/tex] = [tex]\frac{-6}{3}[/tex] = - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (1, 3 )
3 = - 2 + c ⇒ c = 3 + 2 = 5
y = - 2x + 5 ← equation in slope- intercept form
Add 2x to both sides
2x + y = 5 ← equation in standard form