Respuesta :

Answer:

[tex]ln( |1 + u| ) = 7t + \frac{ {t}^{2} }{2} + c[/tex]

Step-by-step explanation:

[tex]integral( \frac{1}{1 + u} )du = \\ integral(7 + t)dt[/tex]

[tex] ln( |1 + u| ) = 7t + \frac{ {t}^{2} }{2} + c[/tex]