The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.10 Find the probability that -2<_x<_2

Answer:
0.6 probability that [tex]-2 \leq x \leq 2[/tex]
Step-by-step explanation:
The probability distribution is given in the table.
Probability that x is between -2 and 2.
Between -2 and 2, inclusive, we have -2, 0 and 2. So
[tex]P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)[/tex]
From the table:
[tex]P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11[/tex]. So
[tex]P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60[/tex]
0.6 probability that [tex]-2 \leq x \leq 2[/tex]