Answer:
[tex]\frac{31}{(5x+2)^2}[/tex]
Step-by-step explanation:
See image for quotient rule
f(x)= numerator = 3x-5
g(x)= denominator = 5x+2
so we have
[tex]\frac{(5x+2)(3x-5)'-(3x-5)(5x+2)'}{(5x+2)^2}\\(3x-5)'=3\\(5x+2)'=5\\\frac{(5x+2)(3)-(3x-5)(5)}{(5x+2)^2}\\\frac{15x+6-(15x-25)}{(5x+2)^2}\\\frac{31}{(5x+2)^2}[/tex]
