Answer:
The two column proof is presented as follows;
Step [tex]{}[/tex] Statement Reason
1 [tex]{}[/tex] [tex]\overline {AC}[/tex] ≅ [tex]\overline {BD}[/tex] Given
[tex]{}[/tex] ∠CAB ≅ ∠DBA
2 [tex]{}[/tex] [tex]\overline {AB}[/tex] ≅ [tex]\overline {AB}[/tex] Reflexive property
3 [tex]{}[/tex] ΔABC ≅ ΔBAD SAS rule of congruency
Step-by-step explanation:
Given that we have;
Segment [tex]\overline {AC}[/tex] of ΔABC being congruent to (≅) segment [tex]\overline {BD}[/tex] on ΔBAD and angle ∠CAB on ΔABC is congruent to angle ∠DBA on ΔBAD, and also that the two triangles share a common side, which is segment [tex]\overline {AB}[/tex], we have;
Segment [tex]\overline {AB}[/tex] is congruent to itself by reflexive property, therefore;
Two sides and an included angle on ΔABC are congruent to the corresponding two sides and an included angle on ΔBAD, which by Side-Angle-Side, SAS, rule of congruency, ΔABC is congruent to ΔBAD
