What is the radius of a hemisphere with a volume of 45729 in, to the nearest tenth
of an inch?

Answer:
Step-by-step explanation:
Use the volume of a sphere formula and then multiply it by .5 to get half of it, since a hemisphere is half of a sphere. Doing that gives us the formula:
[tex]V=\frac{4}{3}\pi r^3\frac{1}{2}[/tex] which simplifies to
[tex]V=\frac{2}{3}\pi r^3[/tex] . Now, filling in what we were given:
[tex]45729=\frac{2}{3}\pi r^3[/tex] which simplifies a bit to
[tex]137187=2\pi r^3[/tex]. We divide by 2π to get
[tex]2183.98918=r^3[/tex] and take the cubed root on your calculator to get that
r = 27.9"
[tex]Volume= 45729in^3\\\\[/tex]
[tex]Radius=r[/tex]
[tex]2/3\pi r^3=45729[/tex]
[tex]r^3=3*45729\\~~~~------\\~~~~~~2*3.14[/tex]
[tex]r^3=21845.06[/tex]
[tex]r=27.95~in[/tex]
hope it helps...
have a great day!!