A 70 kg student now sits in the chair and the same 35 N force is applied to the chair. What is the chair's new acceleration?

Respuesta :

Answer:

0.5 m/s²

Explanation:

Applying,

F = ma............... Equation 1

Where F = Force applied to the chair, m = mass of the student, a = acceleration of the chair

make a the subject of the equation

a = F/m............ Equation 2

From the question,

Given: F = 35 N, m = 70 kg

Substitute these values into equation 2

a = 35/70

a = 0.5 m/s²

Hence the new acceleration of the chair is 0.5 m/s²