Answer:
[tex]h=25[/tex]
Step-by-step explanation:
From the question we are told that:
Velocity [tex]v=40fts[/tex]
The height h function
[tex]\large h=-16t^2+40t[/tex]
Generally time t is mathematically given by
[tex]h'=-32t+40[/tex]
[tex]-32t+40=0[/tex]
[tex]t=\frac{40}{32}[/tex]
[tex]t=1.25[/tex]
Therefore the ball's maximum height is given as
[tex]\large h=-16(1.25)^2+40(1.25)[/tex]
[tex]\large h=-16(1.25)^2+40(1.25)[/tex]
[tex]h=25[/tex]
