Answer:
PQ = 11 m
Step-by-step explanation:
In trapezium PQRS,
PQ and RS are parallel lines and PT is the perpendicular distance between the parallel lines
a = PQ
b =RS = 17 m
d = PT = 14 m
[tex]\frac{(a+b)*d}{2}= 196\\\\\frac{(PQ + 17)*14}{2}=196\\\\(PQ + 17) * 7 = 196\\\\PQ + 17 = \frac{196}{7}\\\\PQ + 17 = 28\\\\PQ = 28 - 17\\\\PQ = 11[/tex]
