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state study on labor reported that one-third of full-time teachers in the state also worked part-time at another job. For those teachers, the average number of hours worked per week at the part-time job was 13. After an increase in state teacher salaries, a random sample of 400 teachers who worked part-time at another job was selected. The average number of hours worked per week at the part-time job for the teachers in the sample was 12.5 with a standard deviation of 6.5 hours. Is there convincing statistical evidence, at the level of α=0.05, that the average number of hours worked per week at part-time jobs decreased after the salary increase?

(A) No. The p-value of the appropriate test is greater than 0.05.
(B) No. The p-value of the appropriate test is less than 0.05.
(C) Yes. The p-value of the appropriate test is greater than 0.05.
(D) Yes. The p-value of the appropriate test is less than 0.05.
(E) Not enough information is given to determine whether there is convincing statistical evidence
answer a show work, please

Respuesta :

Answer: a) no. The p value of the appropriate test is greater than 0.05

Step-by-step explanation:

The statement "No. The p-value of the appropriate test is greater than 0.05." is a correct option (A) is correct.

What is the standard deviation?

It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.

We have:

Sample size n = 400 teachers

Sample mean X = 12.5 hours

Standard deviation S = 6.5 hours

Population mean u = 13 hours

Null hypothesis H0: u = 13

Alternativ hypothesis u <13

T-test:

[tex]\rm t = \frac{x-u}{\frac{s}{\sqrt{n} } }[/tex]

[tex]\rm t = \frac{12.5-13}{\frac{6.5}{\sqrt{400} } }[/tex]

t = -1.5385

Now degree freedom df = n -1  = 400 - 1

df = 399,  α = 0.05

P-value = p[1+t<-1.5385]

P-value = 0.0624

∴ P-value is greater than α because of this the null hypothesis failed.

Thus, the statement "No. The p-value of the appropriate test is greater than 0.05." is a correct option (A) is correct.

Learn more about the standard deviation here:

brainly.com/question/12402189

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