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A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the refrigerator. (PE=MGH(G=9.8M/S²)​

Respuesta :

emanshahzadi929

Answer:

220,500 Joules

Explanation:

PE = (75 kg) x (9.8 [tex]m/s^{2}[/tex]) x (300 m)

PE = (735) x (300)

PE = 220,500 Joules

Answer:

googli moogli

Explanation:

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