Given:
The vertical height of the trapezoid = 2.9 m
The bases of the trapezoid are 2.3 m and 9.3 m.
To find:
The area of the given trapezoid.
Solution:
The area of a trapezoid is:
[tex]A=\dfrac{1}{2}(a+b)h[/tex]
Where, a, b are bases or length of parallel sides and h is the vertical height of the trapezoid.
Putting [tex]a=2.3,\ b=9.3,\ h=2.9[/tex] in the above formula, we get
[tex]A=\dfrac{1}{2}(2.3+9.3)(2.9)[/tex]
[tex]A=\dfrac{1}{2}(11.6)(2.9)[/tex]
[tex]A=16.82[/tex]
Therefore, the area of the given trapezoid is 16.82 square m.
