Answer:
[tex]\sin(N) = 0.66[/tex]
Step-by-step explanation:
Given
[tex]\angle P = 90^o[/tex]
[tex]PO = 48; NP = 55; ON = 73[/tex]
Required
[tex]\sin(N)[/tex]
The given parameters is illustrated with the attached image.
From the attached, we have:
[tex]\sin(N) = \frac{Opposite}{Hypotenuse}[/tex]
[tex]\sin(N) = \frac{PO}{ON}[/tex]
[tex]\sin(N) = \frac{48}{73}[/tex]
[tex]\sin(N) = 0.66[/tex] -- approximated
