Respuesta :

maacastrobr

Answer:

24.24 g

Explanation:

First we calculate how many moles are there in 300 mL of a 0.234 M solution, using the definition of molarity:

  • Molarity = moles / liters

Converting 300 mL to L ⇒ 300 mL / 1000 = 0.300 L

  • 0.234 M = moles / 0.300 L
  • moles = 0.78 moles

Then we convert 0.78 moles of NH₄F into grams, using its molar mass:

  • 0.78 mol * 31.073 g/mol = 24.24 g

Otras preguntas