contestada

A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver

Respuesta :

Answer: [tex]1200\ N[/tex]

Explanation:

Given

Mass of receiver [tex]m=92\ kg[/tex]

Running at a speed of [tex]v=8\ m/s[/tex]

time taken to stop [tex]t=0.6\ s[/tex]

We know, impulse imparted is given by

[tex]\Rightarrow F\cdot dt=m\Delta v\\\Rightarrow F(0.6)=90(8-0)\\\\\Rightarrow F=\dfrac{90\times 8}{0.6}\\\\\Rightarrow F=1200\ N[/tex]

Thus, 1200 N is needed to stop the receiver.