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The mean age of the employees at a large corporation is 35.2 years, and the standard deviation is 9.5 years. A random sample of 4 employees will be selected. What are the mean and standard deviation of the sampling distribution of the sample mean for samples of size 4

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Answer:

35.2 ; 4.75

Step-by-step explanation:

Given that :

Mean age, μ = 35.2 years

Standard deviation, σ = 9.5 years

The mean of the sampling distribution will be equal to the population mean, μ, this is according to the central limit theorem.

The standard deviation of the sampling distribution, is given by : σ/√n

n = sample size = 4

SD of sampling distribution = 9.5/√4 = 9.5 / 2 = 4.75

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