Answer:
-1.5 L/h
Step-by-step explanation:
The volume of water in a reservoir decreased from 24.000L to 18.000L between 06.00 and 10.00.
We need to find the average rate of decrease in volume of water. It can be solved as follows :
[tex]Rate=\dfrac{18-24}{10-6}\\\\=-1.5\ L/h[/tex]
The negative sign shows the decrease in volume. Hence, the rate of decrease in volume of water is 1.5 L/h.
