Answer:
An = 6 + (n-1)5
A25 = 120
Step-by-step explanation:
Given sequence;
6 , 11 , 16 , 21 , 26 , .......
Find:
25th term
Computation:
First term of AP (a) = 6
Common difference (d) = a2 - a1
Common difference (d) = 11 - 6
Common difference (d) = 5
An = a + (n-1)d
So,
An = 6 + (n-1)5
So,
If n = 25
A25 = 6 + (25 - 1)5
A25 = 6 + (24)5
A25 = 6 + 120
A25 = 120
