Answer:
[tex]E_2=80N/C[/tex]
Explanation:
From the question we are told that:
Initial Distance [tex]d_1=40cm=>0.4m[/tex]
Initial Electric field strength [tex]E_1=100N/C[/tex]
Final Distance [tex]d_2=20cm=>0.20m[/tex]
Generally the equation for Electric field is mathematically given by.
[tex]E=\frac{kq}{d^2}[/tex]
[tex]q=\frac{100*(0.4)^2}{K}[/tex]
Substituting q for [tex]d=20cm[/tex]
[tex]E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}[/tex]
[tex]E_2=80N/C[/tex]
